Vertex of the parabola whose equation is y = x2 6x 2.

 Complete the square to put equation  to the form 


     (half the 6 then square it to find the third term and make the LHS into a 
       perfect square.  add the number to both sides )


     (factorise the LHS and simplify the RHS)





In this form, we know that the vertex is (-h , k )
∴ the vertex of this equation is (-(3) , -7 )

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