The number of calories burned c varies directly with the time spent exercising t when then it swats for 4 hours he burns 800 calories which of the following equation show this direct linear variation
a c=800+
b c=4t
c c=t
d c=200t

Option D : c =200t

Step-by-step explanation:

The number of calories burned C varies directly with the time spent exercising T

∴  ∝ t

∴ c = a t

Where a is the constant of proportion

exercising for 4 hours he burns 800 calories

∴ c = 800 when t = 4

∴ 800 = 4 a

∴ a = 800/4 = 200

∴ c = 200 t

The answer is option D : c =200t

is there any photos or whatever?