The decibel level of sound is 50 db greater on a busy street than in a quiet room where the intensity of sounds is 10^-10 watt/m^2.

the level of sound in the quiet room is (10,20, or 100) db, and the intensity of sound in the busy street is (10^-1, 10^-5, or

10^-10) wat/m^2.

use the formula b=10log(i/io) , where b is the sound level in decibels, i is the intensity of sound, and io is the smallest sound intensity that can be heard by the human ear (roughly equal to 1x10^-12 watts/m^2).

my guess would be b and d, but i didn’t actually get out the pen and paper. lol

the answer is 21%.

y=sec x is the correct answer

~batmans wife dun dun

the degrees would remain the same ( the number to the left of the decimal point.

the multiply the decimal by 60 to get the minutes and use the numbers to the left of the decimal point.

then multiply the decimal portion of that by 60 for the seconds and round off as needed.

39 .956652

the 39 remains the degrees.

the minutes = 0.956652 x 60 = 57.39912

the minutes = 57

the seconds = 0.39912 x 60 = 23.95 = 24 ( rounded to nearest tenth)

so 39.956652 = 39 degrees, 57 minutes and 24 seconds

-75.159809

the -75 remains the degrees

the minutes = 0.159809 x 60 = 9.58854

the minutes = 9

the seconds = 0.58854 x 60 = 35.31, rounded to nearest tenth = 35.3 seconds

so -75.159809 = -75 degrees, 9 minutes and 35.3 seconds.

the first coordinate is north or south, since it it positive it is north.

the second number is east or west, because it is negative it is west.

39 degrees, 57 minutes and 24 seconds n

-75 degrees, 9 minutes and 35.3 seconds w