In triangle abc , m angle a=2x+4 and m angle b=6x-58 the exterior angle at c is represented by 5x. find the value of x

The value of x = 18

Step-by-step explanation:

Given m∠A = 2x + 4

          m∠B = 6x - 58

The exterior angle at C = 5x

We should know that:

The exterior angle at C = m∠A + m∠B

∴ 5x = (2x + 4) + (6x - 58)

Solve for x

∴ 5x = 2x + 4 + 6x - 58

∴ 5x = 8x - 54              

∴ 5x - 8x = -54

∴ -3x = -54

∴ x = -54/-3 = 18

So, the value of x = 18

answer: haha (: i’ll go see what it is

step-by-step explanation:

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.