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a) x = 45°

b) AD is parallel to BC.

Step-by-step explanation:

Here, the given angles in the quadrilateral ABCD are:

∠A = ( 2 x)° , ∠B = ( 90)° , ∠C = ( x)°  and ∠D = ( 3x)°

Now, in a quadrilateral: SUM OF ALL INTERIOR ANGLES IS 360°.

⇒∠A+ ∠B+  ∠C +∠D = (180)°

or, ( 2 x)+ ( 90)° + ( x)° +  ( 3x)°  =  (180)°

or, 6 x = 180 - 90 = 270°

or, x = 270/6  = 45°

or, x = 45°

Now, ∠A = ( 2 x)° = 2 x (45°) = 90°

⇒∠A  = ∠B = 90°

So, AD and BC are two lines perpendicular to AB.

⇒ AD  II  BC   (as two liner PERPENDICULAR to the same given lines are PARALLEL to each other)

Hence, AD is parallel to BC.

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

70

step-by-step explanation: