An airplane has 29 seats. the price for a coach seat is $600 in the price for a first class seat is $1050. the airline collected a total of $21,900 for the flight. how many coach seats were sold

19 coach seats

Step-by-step explanation:

let the number of coach seats be C and number of first class seats be F

given that the total number of seats is 29,

C + F = 29 (eq 1)

also given that each coach seat = $600, each 1st class seat is $1050 and a total of $21900 was collected,

600C + 1,050F = 21,900 (eq 2)

we have 2 equations and 2 unknowns, we can solve the system of equations by elimination

(eq 1) x 1,050 gives us:

1,050 (C + F) = 1,050(29)

1,050C + 1,050F = 30,450 (eq 3)

by elimination, subtract eq 2 from eq 3

(1,050C + 1,050F) - (600C + 1,050F) = 30,450 - 21,900

1,050C - 600C = 8,550  

450C = 8550

C = 855 /450

C = 19

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

2(2x + 3) = -4 + 2(2x + 5)

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 6

4x - 6 + 6 = 4x - 6 + 6

4x = 4x

x = x

unlimited solutions.