Agun with a muzzle velocity of 1500 feet per second is fired at an angle of 6 degrees with the horizontal. find the vertical and horizontal components of the velocity to the nearest whole number.

The vertical component of velocity is 156 feet per second

The horizontal component of velocity 1491 feet per second .

Step-by-step explanation:

Given as :

The velocity of gun = v = 1500 feet per sec

The angle made by gun with horizontal = Ф = 6°

Let The vertical component of velocity =

Let The horizontal component of velocity =

Now, According to question

The vertical component of velocity = v sin Ф

i.e   = v sin Ф

Or , = 1500 ft/sec × sin 6°

Or , = 1500 ft/sec × 0.104

∴  = 156 feet per second

So, The vertical component of velocity = = 156 feet per second

Now, Again

The horizontal component of velocity = v cos Ф

i.e   = v cos Ф

Or , = 1500 ft/sec × cos 6°

Or , = 1500 ft/sec × 0.994

∴   = 1491 feet per second

So, The horizontal component of velocity = = 1491 feet per second

Hence,The vertical component of velocity is 156 feet per second

And The horizontal component of velocity 1491 feet per second . Answer

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step-by-step explanation: