The coordinates of a triangle are p(1, 4), q(3, 6), and r(5, 2). the triangle is reflected over a line and its image coordinates are p'(–1, 4), q'(–3, 6), and r'(–5, find the equation of the reflection line.
1. x = –1
2. y = –1
3. y = 0
4. x = 0

Option 4. x = 0

Step-by-step explanation:

we know that

The rule of the reflection of a point across the y-axis is equal to

(x,y) > (-x,y)

The rule for reflecting over the Y axis is to negate the value of the x-coordinate of each point, but leave the y-value the same

The coordinates of triangle PQR are

P(1, 4), Q(3, 6), and R(5, 2)

Applying the rule of the reflection across the y-axis we have

P(1, 4) > P'(-1, 4)

Q(3, 6) > Q'(-3, 6)

R(5, 2)> R'(-5, 2)

The reflection line is the y-axis

Remember that the equation of the y-axis is x=0

therefore

The equation of the reflection line is x=0

true !

step-by-step explanation:

is there any photos or whatever?