a1.0 kg cart moving right at 5.0 -- on a frictionless track
collides with a second cart moving left at 2.0 m/s.
the 1.0 kg cart has a final speed of 4.0 m/s to the left, and the
second cart has a final speed of 1.0 m/s
to the right.
what is the mass of the second cart?
consider rightward as the positive direction.

3.0 kg

Step-by-step explanation:

Momentum before collision = momentum after collision

m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂

(1.0 kg) (5.0 m/s) + m (-2.0 m/s) = (1.0 kg) (-4.0 m/s) + m (1.0 m/s)

5.0 kg m/s + m (-2.0 m/s) = -4.0 kg m/s + m (1.0 m/s)

9.0 kg m/s = m (3.0 m/s)

m = 3.0 kg

answer: -1

step-by-step explanation:

6,250

step-by-step explanation:

to get the area, multiply 360 by 160.(57,600)

to find out how many bags of fertilizer it will take, first figure out how many square feet one bag can hold. divide 1000 by 8(125) to get the unit rate(how many square feet one pound of fertilizer can hold)and multiply it by 50(6250). if i haven't made a mistake, that is the answer.