In trapezium abcd, as shown in the figure, ab is parallel to dc, ad=dc=bc=20cm and ‹a=60°. find: (i) length of ab (ii) distance between ab and dc

AB = 40 cm

Distance = cm

Step-by-step explanation:

Draw two heights DE and CF. These heights together with bases of trapezoid form rectangle DEFC. In this rectangle, DC=EF=20 cm.

Consider right triangle ADE. In this triangle, angle ADE has the measure of 30° (the sum of the measures of all interior angles is always 180°, so m∠ADE=180°-60°-90°=30°)

Leg opposite to 30° angle is equal to half of the hypotenuse, so

Similarly, in triangle CBF, BF=10 cm.

Hence,

The height of the trapezoid (the second leg of triangle ADE) is the distance between DC and AB. By the Pythagorean theorem,

hey there!

if she's saving for six months, let's divide the total number we need for the trip by six, dividing it into the amount that needs to be saved for each month.

500 ÷ 6 =

she needs to save at least this amount each month, so we should use this symbol: ≥

let x be the amount she saves each month.

your final answer is x ≥

hope this !

yes

step-by-step explanation:

yes