Write the standard form of the equation of the circle that passes through the origin, (2.8,0), and (5,2)

2.2y-2x = 0

Step-by-step explanation:

The standard form of the equation is normally y = mx + c where m is the gradient or the slope value while c is the y intercept.

As we know, the line passes through the origin, hence, it has no y intercept. This means our c has a value of zero.

What is left to find is the slope of the line.

m = (y2 - y1)/(x2 - x1)

m = (2 - 0)/(5 - 2.8)

m = 2/2.2 = 0.9091

so the standard form of the equation of the line is y = 0.9091x

OR

y = (2/2.2)x

OR

2.2y = 2x

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

i think the answer is seven, for if i'm being useless °ω°

step-by-step explanation: