Assume the random variable x is normally distributed, with mean u=50 and standard deviation sd=6. find the 15 th percentile.

44.85.

Step-by-step explanation:

We have been given that the random variable X is normally distributed, with mean u=50 and standard deviation SD=6. We are asked to find the 15th percentile.

We will use normal distribution table to find the z-score corresponding to 15th percentile or 0.15.

Using normal distribution table, we will get z-score of .

Now, we will use z-score formula to find corresponding x-value to z-score of .

, where,

z = Z-score,

x = Sample score,

= Mean,

= Standard deviation.

Upon substituting our given values, we will get:

Therefore, the 15th percentile is 44.85.

cosine

step-by-step explanation:

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.