Mike and menna were instructed to graph the function y = 12 x + 1. their graphs are shown.
the figure shows two graphs in the xy-plane. the graph on the left is labeled as mike's graph. the values on the x-axis range from negative 8 to 8 in increments of 2 and the values on the y-axis range from negative 8 to 8 in increments of 2. a line is shown which intersects the x-axis at negative 0.5 and y-axis at 1. the graph on the right is labeled as menna's graph. the values on the x-axis range from negative 8 to 8 in increments of 2 and the values on the y-axis range from negative 8 to 8 in increments of 2. a line is shown which intersects the x-axis at 2 and y-axis at 1.

which student graphed the function correctly?
what mistake did the other student make?

The function is y = 2x + 1.

And mike graphed the function correctly.

Menna took the point where the function touches x-axis incorrectly.

Instead of (-1/2,0), Menna took it as (-2,0)

Step-by-step explanation:

The equation y = mx +c indicates a straight line whose slope is m

And y-intercept is c.

y-intercept is nothing but the distance between origin and point where the graph crosses the y-axis (0,c).

Now, this graph crosses x-axis when y = 0.

⇒ mx + c = 0;       ⇒ x = .

Now, by comparing y = 2x + 1 with y = mx + c.

m=2 and c=1

⇒ the graph should crosses y-axis at (0,c) = (0,1)

And touch x-axis at ( , 0) = (,0)

⇒ mike graphed the function correctly.

Menna took the point where the function touches x-axis incorrectly.

Instead of (-1/2,0), Menna took it as (-2,0)

ljn

step-by-step explanation:

you ignore the remainder, therefore the answer is y = x+2

step-by-step explanation:

you have to divide the denominator by the numerator. you can use synthetic division or long division.

[-5] .     1 .     7 .     11

x + 2 + 1/x+5