Determine the type and number of solutions of x^2 + 10x − 25 = 0. a two real solutions b one real solution c two imaginary solutions

two real solution

Step-by-step explanation:

x^2 + 10x − 25 = 0

we can solve this by finding out the value of x

lets assume the equation is   a\times x^{2}+b\times x+c=0

x=-b\pm \sqrt{(b^{2}-4ac)}\div 2a

x=-10\pm\sqrt{100+4*25}\div2

x=-5\pm5\sqrt2

then we get both real value of x

so two real solution

1. a^4+8a^3+24a^2+32a+16

2.y^8+8y^7+28y^6+56y^5+70y^4+56y^3+28y^2+8y+1

3.x^6-3x^4y^2+3x^2y^4-y^6

the answer will be 80.