Consider the following data collected in two recent surveys of whether voters in cities a and b favor a ballot proposition in the next election. city sample size in favor a 615 463 b 585 403 suppose you're going to find a confidence interval for the difference between the population proportions in the two cities. what's the standard error of the estimate of the difference between the two proportions?

Standard error of the estimate of the difference between the two proportions=0.0259

Step-by-step explanation:

Given that the following data collected in two recent surveys of whether voters in cities A and B favor a ballot proposition in the next election.

City                         A                  B            Total

Sample size          615            585             1200

Favour X               463           403               866

Proportion p         0.7528     0.6889        0.7217

Std error for difference

=

p =0.7217

1-p = 0.2783

by substituting p and n1 = 615 and n2 = 585 we get

Std error = 0.0259

Standard error of the estimate of the difference between the two proportions=0.0259

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2