Compute δy and dy for the given values of x and dx = δx. (round your answers to three decimal places.) y = x , x = 1, δx = 1 δy = dy =

Δy = 1

dy = 1

Step-by-step explanation:

Data provided in the question:

dx = Δx

y = x

x = 1,

Δx = 1

Now,

we know,

Δy = f( x + Δx ) - f(x)

also, we have

y = f(x) = x

thus,

f( x + Δx ) =  x + Δx

Therefore,

Δy = ( x + Δx ) - x

on substituting the respective values, we get

Δy = ( 1 + 1 ) - 1

or

Δy = 1

and,

dy = f'(x) =

or

dy = 1

x=0

step-by-step explanation:

step-by-step explanation:

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