Apoint is reflected in the x-axis the new point is (5, -3.5) what is the distance between the two points? urgent pls

Distance between two points is 7

Explanation:

This is a question based on reflection of point w.r.t line. During reflection we can see the mirror image with t-shirt print inverted.But the  distance from mirror remains same.

Assume a point (x,y), and it reflect in x-axis, then x-axis serves as the mirror, and the new point is (x,-y), because the distance from the mirror remains same. If the reflection of the point is (x,y) in y-axis, then y-axis serves as the mirror, and the new point is (-x,y). And if you reflect (x,y) in y=x line, then new point will be (y,x).

So considering the above question, if new point is (5, -3.5), then the original point must be (5, 3.5)

Distance between two points and is given by:

d(P, Q) =

So distance = 7

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation: