Charles wants to determine which car is the fastest. the actual speed of four cars is shown below:

cars a b c d
speed (in km/h) 60.34 60.32 60.33 60.35

if the speedometer can only measure to the nearest tenth of a second, which car will have a different measurement?

Step-by-step explanation:

Given that Charles wants to determine which car is the fastest. The actual speed of four cars is shown below:

Cars                           A                 B          C         D

Speed (in km/h)60.3460.3260.33      60.35

Speed (in m/s)         16.761      16.755    16.758     16.763

Rounded off            16.76        16.76      16.76        16.76

When measured in km/hour, the order from least to greatest is

B, C, A and D

When measured in m/sec, when rounded off to nearest 10th we get

all are having equal speeds.

1.4

2.3

step-by-step explanation:

the formula for the constant of variation is

y= kx

divide each side by x

y/x =kx/x

y/x =k

we know a and y

1.   y/x = k

4/1 =4

check the other values to make sure they are the same

8/2 = 4   12/3 =4   and 16/4 =4  

the constant of variation is 4

2.   y/x = k

3/1 =3

check the other values to make sure they are the same

6/2 = 3   9/3 =3   and 12/4 =3  

the constant of variation is 3