Alexander and jo live 5 miles apart. they decide to leave their homes at 3 p. m. and travel toward each other. if alexander bikes 14 miles per hour and jo jogs 6 miles per hour, when will they meet?

Step-by-step explanation:

Here is an illustration of the problem:

             >|<

            A                                  t                     J

Alex and Jo start from their separate homes and drive towards one another.  The t indicates the time at which they meet, which is the same time for both.  Filling in a d = rt table:

              d           =        r        x        t

Alex                              14                t

Jo                                   6                t

The formula for motion is d = rt, so that means that Alex's distance is 14t and Jo's distance is 6t.

                      14t                               6t

   >|<

   A                                       t                      J

The distance between them is 5 miles, so that means that Alex's distance plus Jo's distance equals 5 miles.  In equation form:

14t + 6t = 5 and

20t = 5 so

t = .25 hours or 15 minutes.

If they leave their homes at 3 and they meet 15 minutes later, then they meet at 3:15.

idk

step-by-step explanation:

the answer is 31.27mph