Luis hizo un viaje en el coche en el cual consumio 20 l de gasolina. el trayecto lo hizo en dos etapas en la primera consumio 2/3 de la gasolina que tenia en el deposito y en la segunda, la mitadque le quedaba. ¿cuanta gasolina habia en el deposito?

Step-by-step explanation:

Let be "x" the amount of gasoline in liters that the car's tank had at the beginning of the trip.

 1. In the first part of the trip the amount of gasoline the car used can be expressed as:

2. After the first part of the trip, the remaining was:

3. In the second part of the trip the car used of the remaining. This is:

4. The total amount ot gasoline used in this trip was 20 liters.

5. Then, with this information, you can write the following equation:

6. Finally, you must solve for "x" in order to find its value. This is:

option 3 . (5x + 1) - (-10x + 6)

step-by-step explanation:

option 1 :

(4x + 3) + (-9x + 4)

or 4x+3 -9x + 4

or -5x + 7

option 2

(x - 2) - (6x - 9)

or x-2-6x + 9

or -5x + 7

option 3

(5x+ + 6)

or 5x + 1 + 10x -6

or 15x -5

option 4

-4x+2x+7-3x

-7x + 2x + 7

-5x + 7

hence only option 3 did   not satisfy the given simplify expression.