Two perpendicular lines have opposite y-intercepts. the equation of one of these lines is

y=mx+b. express the x-coordinate of the intersection point of the lines in terms of m and b.

the x-coordinate is x =

plz me and fast!

 The required x-co-ordinate of the point of intersection of two lines is

Step-by-step explanation:  Given that two perpendicular lines have opposite y-intercept and the equation of one of the lines is

We are to express the x-coordinate of the intersection point of the lines in terms of m and b.

Let the slope and y-intercept of the other line be s and c respectively.

Since the product of the slopes of two perpendicular lines is -1 and -b is the opposite of b, so we have

and c = -b.

That is, the equation of the other line is

Comparing the equations of both the lines, we get

Thus, the required x-co-ordinate of the point of intersection of two lines is

80° is the measure of gh

step-by-step explanation:

circle f is congruent to circle j

we have two circle with center f and j.

both circles are congruent. the radius of the circle would be equal.

see the attachment for the circle.

we are given ∠efd ≅ ∠gjh

therefore, arc (ed) = arc (gh)     (∴ circle f is congruent to circle j)

but ∠dfe=80°=arc (ed)

therefore, arc (gh) = 80°

thus, 80° is the measure of gh