Aboy thinks he has discovered a way to drink extra orange juice without alerting his parents. for every cup of orange juice he takes from a container of orange juice, he pours one cup of water back into the container. if he completes this process three times on the same container of juice, the resulting mixture will be exactly 50% water and 50% juice. how many cups of orange juice were originally in the container. (p. s its not 6)

x=4.8473 cups

Step-by-step explanation:

Concentration of Liquids

It measures the amount of substance present in a mixture, often expressed as %. If there is an volume x of a substance in a total volume mix of y, the concentration is given by

It we take a sample of that mixture, we must consider that we are getting only the substance, but all the mixture (assumed it has been uniformly mixed). For example, if we take a glass of liquid from a 80% mixture of juice, the glass will also have a 80% of juice.

Let's solve the problem sequentially. At first, let's assume all the container is full of x cups of juice. Its concentration is 100%. Now let's take 1 cup of pure juice and replace it by 1 cup of pure water. The new amount of juice in the container is

x-1 cups of juice.

The new concentration is

The boy takes a second cup of liquid, but this time it's not pure juice, it has a mixture of juice and water with a concentration computed above. Now the amount of juice is

cups of juice.

Simplifying, the cups of juice are

The new concentration is

For the third time, we now have

cups of juice.

Simplifying, the final amount of juice is

And the final concentration is

According to the conditions of the question, this must be equal to 50% (0.5)

Taking cubic roots

Operating and joining like terms

Solving for x

Let's test our result

Final concentration:

answer: 4/6 =5/7.5

step-by-step explanation: it is based on scale and the scale between the two is 1.25. the answer is correct but i dont know if i explained it right

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

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