The mass of two sacks of potatoes is 168 grams. one-eight of the mass of sack a and three-quarter of the mass of sack b is 76 grams. write an equation to find the mass of sack a.

1/8(A)+(3/4)(168-A)=76 is an equation to find the mass of A, the mass of A is 80 grams.

Step-by-step explanation:

What do we know?

Both sacks together are 168 grams. Therefore;

A+B=168

One eighth of sack A and three quarters of sack B is equal to 76 grams. Therefore;

1/8(A)+(3/4)B=76

Let's solve using the substitution method to find A. First, we need to isolate and then substitute B for an expression containing A.

A+B=168

B=168-A

Now that we have isolated B, we can substitute '160-A' for B in the other equation.

1/8(A)+(3/4)(168-A)=76

1/8(A)-3/4(A)+126=76

1/8(A)-3/4(A)+126=-50

-5/8(A)=-50

A=80

use substitution to solve each system of equations. y = x + 5 3x + y = 25 62/87,21 y = x + 5 3x + y = 25 substitute x + 5 for y in the second equation. substitute the solution for x into either equation to find y. the solution is (5, 10)

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step-by-step explanation: