The length, width, and height of a rectangular prism is a, (a-13), and (a+13) respectively, which statement best describes (a-13)

pls

a. the width of the rectangular prism is 13 units less than the length
b. the height of the rectangular prism is 13 units more than the lenght
c. the width of the rectangular prism is 13 units less than the height
d. the length of the rectangular prism is 13 units less than the weight

Option A

The width of the rectangular prism is 13 units less than the length

Solution:

Given that, the length, width, and height of a rectangular prism is a, (a-13), and (a+13) respectively

From given question,

Length of rectangular prism = a

Width of rectangular prism = a - 13

Height of rectangular prism = a + 13

We have to find which statement best describes (a - 13)

From given (a - 13) means Width of rectangular prism

Therefore,

Width of rectangular prism = (a - 13)

We know that from given "a" denotes Length of rectangular prism

So we get,

Width of rectangular prism = (Length of rectangular prism - 13)

So the above expression means that width is 13 units less than length

So option A is correct. The width of the rectangular prism is 13 units less than the length

Let us also analyse the options one by one

a.) the width of the rectangular prism is 13 units less than the length

Which is written mathematically as,

width = length - 13 = a - 13

So this option is correct

b. the height of the rectangular prism is 13 units more than the length

Which is written mathematically as,

height = 13 + length = 13 + a

So this option does not describes (a - 13)

c. the width of the rectangular prism is 13 units less than the height

Which is written mathematically as,

width = height - 13 = a + 13 - 13 = a

So this option does not describes (a - 13)

d. the length of the rectangular prism is 13 units less than the height

Which is written mathematically as,

length = height - 13 = a + 13 - 13 = a

So this option does not describes (a - 13)

answer: 1inch=7days  

12inch=12*7=84days

step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)