You want to know if high-school females score differently than high-school males on a standardized test. you take a random sample of 28 males and 27 females from high schools across the country and record their scores. which confidence interval would you use to analyze these data?

Step-by-step explanation:

Random sample size of males, n₁ = 28

Random sample size of males, n₂ = 27

Here,

If n₁ < 30 & n₂ < 30,

we use t-distribution

Therefore,

The confidence interval chosen will be

⇒

Here,

is mean of sample n₁

and,

is mean of sample n₂

s is the standard deviation

the value of 't' can be obtained from the standard t- distribution table

from the figure we get,

the x axis shows   the months and,

the y-axis shows the number of satisfied customer.

each line or each cell in upward direction (y-axis) shows 500.

the appropriate scale for the y - axis is: -

a = 2000 customers

b = 4000 customers

c = 6000 customers

d = 8000 customers

e = 10000 customers

f = 12000 customers

g = 14000 customers

55.44 inches

step-by-step explanation:

part a. assuming a perfectly linear relationship, we can find the slope from the first two data points.

slope = m = (change in rainfall)/(change in years)

= (61.80 -62.33)/(2005 -2004) = -0.53/1 = -0.53

then the point-slope form of the equation of the line can be written as

y = m(x -h) +k . . . . . m = -0.53, (h, k) = (0, 62.33)

y = -0.53x +62.33 . . . x = years after 2004

part b. in 2017, x = 2017 -2004 = 13. then the predicted rainfall is

y = -0.53·13 +62.33 = 55.44 . . inches

the predicted rainfall in 2017 is 55.44 in.