There are 3 boxes. first box contains 100 components of which 20 % are defective, second box contains 200 components of which 25 % are defective, third box contains 300 components of which 40 % are defective. box is selected randomly and from this box one component is selected randomly. the chosen component turned out to be defective.

determine the probability that it came from
a) second box.
b) third box.

Step-by-step explanation:

Given that there are 3 boxes. First box contains 100 components of which 20 % are defective, second box contains 200 components of which 25 % are defective, third box contains 300 components of which 40 % are defective.

Box is selected randomly and from this box one component is selected randomly. The chosen component turned out to be defective.

Here A1, A2 and A3 events from drawing I, II and III box are mutually exclusive and exhaustive

B = The drawn ball is defective

Required probability

a) second box = P(A2/B)

=

(by Bayes theorem of conditional probability)

=

b) third box = P(A3/B)

=

3.76%

step-by-step explanation:

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq