Giving a test to a group of students, the grades and gender are summarized below a b c total male 2 19 7 28 female 4 9 14 27 total 6 28 21 55 if one student is chosen at random, find the probability that the student was female or got a(n) "b". ( enter a reduced fraction.)

46/55

Step-by-step explanation:

A B C Total

Male. 2 19 7 28

Female. 4 9 14 27

Total. 6 28 21 55

Total number of students = 55

Pr of picking a female = number of females / total number

= 27/55

There are 27 females and 28 people got a B

Number of females or those who got a B = 27 + 28 = 55

Subtract off 9 females who got B to help correct for double counting . We have 55 - 9 = 46

This means there are 46 people who either got a B, are females or are females who got a B

Pr(female or got a B) = number who are females or got a B / total number

= 46/55

15

step-by-step explanation:

we are given the following expression and we are to solve it and find the product:

-13 × (-5)

solving the given expression in the standard order of solving a mathematical expression, beginning with the opening of brackets and then multiplying the terms and changing their signs.

-3 × -5 = 15 (answer is positive because when negative is multiplied with negative, it gives a positive answer)