Astack of 45 dimes is divided into three piles in the ratio 1/6 : 1/3 : 1/4.
1. how many dimes are in the pile with the least number of dimes?

10 dimes

the pile with the least number of dimes have 10 dimes

Step-by-step explanation:

Given;

Total number of dimes of the stack = 45

Ratio of division into piles = 1/6 : 1/3 : 1/4

Multiplying the ratio through by 12.

12(1/6 : 1/3 : 1/4) = 2 : 4 : 3

The least number of dimes in a pile(Nl) is that of the least ratio; which is 2

Ni = 2/(2+4+3) × 45

Ni = 2/9 × 45

Ni = 10 dimes

Therefore, the pile with the least number of dimes have 10 dimes

10 dimes

Step-by-step explanation:

First we get rid of the fractions. Multiply everything by 12. So the new ratio is 2:4:3. Then add 2+3+4 which is 9. So 45/9=5, and 5*2 (which is the smallest number in the ratio) is 10. So the answer is 10 dimes.

you need to show the graph

step-by-step explanation:

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