Outline the necessary transformations to prove cbf = edf using a paragraph proof. be sure to name specific sides or angles used in the transformation and any congruency statements.

See the explanation.

Step-by-step explanation:

Given  CB║ED And CB≅ED

Since it is given that CB≅ED

The ΔDEF is a reflection of ΔCBE along point 'E'

So, the point 'E' is center of reflection.

And we know under point reflection the images do not change size and shape.

So the sides of both triangles are same, angle will be the same.

Here we can see ∠DEF = ∠BCF  and ∠EDF=∠CBF  also CB=ED

Then ΔDEF≅BCE

Both of these figures are congruent to each other. We know this because we are given that CB and ED are about equal to each other. We also can see that Triangle DFE is reflected across point  E.  Reflections do not impact sides length or shapes size. Triangle EDF is congruent to Triangle CBF.

Step-by-step explanation:

Above

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step-by-step explanation:

distance formula is d=√(x2-x1)^2   +   (y2-y1)^2