Need figuring this out and would like you to explain how you did it .

Step-by-step explanation:

Since DE is parallel to AC, then triangle DBE is similar to triangle ABC. It means that

AB/DB = BC/BE = AC/DE

Also, the length of BA is BD + DA

BD + DA = 18 + 36 = 54

Also, BC = BE + EC

BC = a + 12

Since triangle DBE is similar to triangle ABC, then

DB/AB = EB/CB. Therefore,

18/54 = a/(a + 12)

Cross multiplying the left hand side of the equation by (a + 12) and the right hand side of the equation by a, it becomes

18(a + 12) = 54 × a

18a + 216 = 54a

Subtracting 18a from the left hand side of the equation and the right hand side of the equation by , it becomes

18a - 18a + 216 = 54a - 18a

36a = 216

Dividing the left hand side of the equation and the right hand side of the equation by 36, it becomes

36a/36 = 216/36

a = 6

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option

none cuz there are no "following statements" regarding the question

step-by-step explanation: