The area of a bulletin board is 55 ft2. the length is nine feet less than four times the width. find the length and the width, in feet, of the bulletin board.

The length and width are 11ft and 5ft respectively

Step-by-step explanation:

let the

length = L

Width = W

Area = LW = 55

The length is nine feet less than four times the width

L = 4W - 9

W (4W - 9) = 55

4W^2 - 9W -55 = 0

4W^2 - 20W + 11W - 55 = 0

4W(W - 5) + 11(W - 5) = 0

(W - 5)(4W + 11) = 0

W - 5 = 0 , 4W + 11=0

W = 5 or  - 11/4

since the width cannot be negative, W = 5

LW = 55

L = 55/5

L = 11

The length and width are 11ft and 5ft respectively.

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11

it’s the first one your welcome