1-use the vertex and intercepts to sketch the graph of the quadratic function. give the equation of the parabola's axis of symmetry. use the graph to determine the domain and range of the function.

f(x)=(x+4)^2−9

2-

a. graph

f left parenthesis x right parenthesis equals negative x squared minus 4 xf(x)=−x2−4x

by determining whether its graph opens up or down and by finding its vertex, axis of symmetry, y-intercept, and x-intercepts, if any.

b. determine the domain and the range of the function.

c. determine where the function is increasing and where it is decreasing

1) 1st graph below x-intercepts S={-7,-1}

2) Opens Down Vertex: (-2,4) Axis of Symmetry x-intercept

B Domain:

Range

C This  function increases from And decreases from

Step-by-step explanation:

1) The vertex of the parabola is found when we rewrite the common formula:

Into this way:

The Vertex is found by:

That's why we could rewrite the trinomial as this:

Give the equation of the parabola's axis of symmetry, this is given by tracing a vertical line through the parabola vertex.

The intercepts are the roots/zeros:

Domain:

Since the function has no restrictions therefore it is continuous and defined for any value of x ∈ Real Set

Range

As the minimum point -9 is lowest y-coordinate the Range includes this value up to infinite values

(First Graph)

2)

As the parameter a <0 then the graph opens down.

Vertex:

Axis of Symmetry

x-intercept

y-intercept

c=0 then (0,0).

B Domain:

Similarly, since the function has no restrictions therefore it is continuous it is defined for any value of x ∈ Real Set

Range

C

This  function increases from Or we can represent this interval like this:

And decreases from

robert puts 2 in each row

a: 1/6, j: 1/4

step-by-step explanation: you are welcome