Which equations represent the line that is perpendicular to the line 5x – 2y = -6 and passes through the point
(5,-4)? select three options.
oy=-x-2
2x + 5y = -10
2x - 5y = -10
cy+4= (x-5)
dy -4 = {(x + 5)

2x + 5y = - 10, Cy + 4 = (x-5)

Dy - 4 = (x+ 5)

Step-by-step explanation:

Equation of the line

5x - 2y = -6

Conditions for perpendicularity

m1 x m2 = -1

To get m1, rearrange the equation

2y = 5x + 6

y = 5x/2 + 3

n1 = 5/2 and m2 = -2/5

To get C

y = mx +c

-4 = -2 x 5/5 + C

-4 = -2 + C

C = -4 + 2

C = -2

To get the equation of the second line

y = -2x/5 - 2

Multiply through by 5

5y = -2x - 10

2x + 5y = 10.

y+4=-(2/5)(x-5)

y=-(2/5)x-2

2x+5y=-10

Step-by-step explanation:

yes

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step-by-step explanation:

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!