Two circles of radii 5 cm and 4 cm intersect at two points and the distance between their centres is 3 cm. find the length of the common chord.

8 cm

Step-by-step explanation:

Two circles of radii 5 cm and 4 cm intersect at two points D and E.

The distance between their centers (points A and C) is 3 cm.

Consider triangle ACD. In this triangle,

AC = 3 cm (distance between centers)

AD = 5 cm (radius of larger circle)

CD = 4 cm (radius of smaller circle)

So, this is right triangle and therefore, AC is the height of isosceles triangle ADE (triangle ADE is isosceles, because AE = AD).

The height of the isosceles triangle drawn to the base is its median, so CD = CE = 4 cm, hence

DE = 4 + 4 = 8 cm

6,250

step-by-step explanation:

to get the area, multiply 360 by 160.(57,600)

to find out how many bags of fertilizer it will take, first figure out how many square feet one bag can hold. divide 1000 by 8(125) to get the unit rate(how many square feet one pound of fertilizer can hold)and multiply it by 50(6250). if i haven't made a mistake, that is the answer.