10
the velocity, vm/s, of a particle moving in a straight line, at time t seconds is given by
v=1+9/t^2
for 1 is less than or equal to t which is less than or equal to 3. when t=3, the particle is 6m from a fixed point o
on the line.

find the acceleration when t=2
find an expression in terms of t for its distance from the fixed point.
find the distance travelled between t = 1 and 1 = 3.
[4]

Acceleration when time is =

Distance

Distance travelled between and is

Step-by-step explanation:

Velocity

Acceleration(a): Rate of change of velocity.

at

Distance(s):

Distance between

what? that isnt a question

step-by-step explanation:

the correct option is:

b. a value of the variable that makes the polynomial equal to zero.

the root or roots of a polynomial are the values of the variable that makes the polynomial equal to 0. we can find the roots of a polynomial making the expression equal to 0 and then, isolating the variable (it it has just one variable).

for example, given the following polynomial:

the root or zero of the polynomial, can be found by making the expression equal to 0, and then, isolating the variable, so, finding the root we have:

therefore, we have that the root of the polynomial is equal to 2.

we must remember that the number of roots that a polynomial can have, will depend on the degree of the polynomial, a first degree polynomial have will have one single root, a second degree polynomial (quadratic expression) may have two roots and so.

hence the correct option is:

b. a value of the variable that makes the polynomial equal to zero.

have a nice day!