The probability of rolling a die and getting a 6 is of course 1/6 and the probability of not getting a 6 is 5/6. if you roll the same die 8 times, what is the probability that 6 will show up twice?

0.261

Step-by-step explanation:

We use the Bernoulli trial method to solve this. The form of the answer goes thus:

P = nCr * x^2 * y^6

Where n is the total number of trials which is 8, while r is the expected number of success, 2 in this case. x is the probability of success 1/6 while y is the probability of failure 5/6 in this case.

P= 8C2 * (1/6)^2 * (5/6)^6

P= 28 * 0.028 * 0.335 = 0.261

good for u

step-by-step explanation:

8 apples are left.

step-by-step explanation:

10-2=8

10 apples

take 2

now u have 8