The height h (in feet) of a certain rocket t seconds after it leaves the ground is modeled by latex: h\left(t\right)\: =\: -16t^2+64t+12.h ( t ) = − 16 t 2 + 64 t + 12.how long does it take the rocket to reach the maximum height?

76 feet

Step-by-step explanation:

h = -16t^2 + 64t + 12

The maximum height will be reached after -b/2a secs

a = -16 , b = 64, c= 12

-b/2a = -64/2(-16)

= -64/-32

= 2 secs

The maximum height = -16(2)^2 + 64(2) + 12

= -16(4) + 128 + 12

= -64 + 128 + 12

= 76 ft

Step-by-step explanation:

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation:

mean, 40.6

step-by-step explanation: