Question 2

1 pts

a health insurance plan has a $50 enrollment fee and a copayment of $5 for each doctor visit. the function f(x) = 5x + 50 gives the cost of x doctor visits. what is

the range of this function?

(50, 55, 60, 65.]

1555, 105, 155,

next

they

(50,55,60,)

Step-by-step explanation:

Given that a health insurance plan has a $50 enrollment fee and a copayment of $5 for each doctor visit.

The function f(x) = 5x + 50 gives the cost of x doctor visits

Here x is the no of visits.

No of visits is an independent variable while f(x) total cost is a dependent variable on x

slope = 5 which indicates for each visit extra, extra cost is 5 dollars

Enrollment fee = 50 = fixed cost

Hence domain would be

x =0,1,2,3

So range is

(50,55,60,)

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11