You manage a restaurant. on any given day you sell on average 20 dinners: 3 fish dinners (0.15),6 chicken dinners (0.30), 6 pork dinners (0.30), and 5 steak dinners (0.25).what is the probability that today you sell 2 fish dinners, 9 chicken dinners, 5 pork dinners, and 4 steak dinners? what probability distribution did you use?

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3

a28=58

step-by-step explanation:

a1=a1+(n-1)d

a28= 4+ (28-1)2

a28=4+(27)(2)

a28=4+54

a28=58

you could deduce the conclusion directly using the facts pertaining to the specific situation.

hope this .