Mathematics, 24.12.2019 23:31, jay1462

Use the value of the first integral i to evaluate the two given integrals. i = integral^3_0 (x^3 - 4x)dx = 9/4 a. integral^3_0 (8x - 2x^3)dx b. integral^0_3 (4x - x^3)dx c. integral^3_0 (8x - 2x^3)dx =

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Use the value of the first integral i to evaluate the two given integrals. i = integral^3_0 (x^3 - 4...