Given: ln ⊥ km ln = 16 ft m∠k = 25°, m∠m = 55° find: radius r

R= 20.88 ft

Step-by-step explanation:

See the diagram attached, this satisfies the condition, ΔKLM is enclosed in a circle of radius R.

LN=16 ft (given)

The value of KM is 2R because as the ∠KLM forms an angle of 90°, therefore, the line KM passes through the center.

Area of a triangle =

Now let's find he area of the ΔKLM=

                                                          =

Also the area can be found out by =( As KLM is a right angled triangle)

KL= KM cos 25°= 2R cos 25°

LM= KM cos 55°= 2R sin 25°

Area= x 2R cos 25°x 2R sin 25 °

      = sin 50°

sin 50°= 16R

R sin 50°=16

R= 20.88 ft

225x²+4=0

225x²=0-4

225x²=-4

x²=-4/225

x=±√-4/225

answer: im gonna go with milli

step-by-step explanation: