Which number is the odd one out? 9678 4572 5261 5133 3527 6895 7768

3527

Step-by-step explanation:

consider all the numbers given , the sum of the first two digits and the last two digits sum up to be the same.

the first number is 9678

9+6 = 15

7+ 8 = 15

Second number: 4572

4 + 5 = 9

7 + 2 = 9

Third number : 5261

5+ 2 = 7

6 + 1 = 7

Fourth number : 5133

5 + 1 = 6

3 + 3 = 6

Fifth number : 3527

3 + 5 = 8

2 + 7 = 9

Sixth number : 6895

6 + 8 = 14

9 + 5 = 14

Seventh number : 7768

7 + 7 = 14

6 + 8 = 14

Considering all the numbers , the fifth number is the odd one out

c

step-by-step explanation:

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,