the cost per week of running a boarding house is partly constant and partly
varies with the number of students in the hostel. if it costs n3500.00 a week for
25 students, and n6000.00 for 50 students. find the cost of running the boarding
house for 600 students.

the cost of running the boarding

house for 600 students is N61,000

Step-by-step explanation:

Let C represents cost

K1 represents first constant

K2 represents second constant

C= k1+k2n

3500 = k1 + 25 k2 Eqn(1)

6000= k1 + 50 k2 Eqn(2)

Subtract eqn(1) from eqn(2)

2500= 25k2

K2= 2500/25

K2= 100

To get k1 from eqn(1)

3500 = k1 + 25 k2

Substitute the value of k2

3500 = k1 + 25 (100)

3500= k1 +2500

K1= 3500- 2500

K1= 1000

The equation connecting them;

C= 1000+ 100n

The cost of running the boarding

house for 600 students is

n= 600

C= 1000+ 100(600)

C= 1000+60000

C= N 61,0000

answer: the 4 kilogram bag

step-by-step explanation: this is because if you divide the number of kilograms into the total it will tell you how much each individual kilogram would be worth. 2 kilos is 7 and change 3 would be around 6 ish and the 4 kilo would be 4.6 and change and the 5 kilos would be like 4.88

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50