Each lenght is in metres calculate dc

Step-by-step explanation:

ED is greater than BC

the line from B to ED ^ (which i drew ) the point it touches ED name it X. so EX will be 2 ( ED-BC)(6-4).

then u have a triangle. EX, XB and EB.

you have length of EX(2) and u have hypotenuse. so u can calculate XB using Pythagoras theorem.

15.1²=2²+XB²

15.1²-2²=XB²

224.01=XB²

XB=14.97

since XB and DC are parallel ( a rectangle is forming XBCD) so DC is also 14.97

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.