Mathematics, 21.12.2019 19:31, blackwelle72

Factor completely: 3x^2 − 17x − 28
a.
(3x + 4)(x + 7)
b.
(3x + 4)(x − 7)
c.
3x^2 − 17x − 28
d.
(3x^2 + 4)(x − 7)

Answers: 2

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Factor completely: 3x^2 − 17x − 28
a.
(3x + 4)(x + 7)
b.
(3x + 4)(x − 7)<...

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Factor completely: 3x^2 − 17x − 28 a. (3x + 4)(x + 7) b. (3x + 4)(x − 7) c. 3x^2 − 17x − 28 d. (3x^2 + 4)(x − 7)

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Factor completely: 3x^2 − 17x − 28
a.
(3x + 4)(x + 7)
b.
(3x + 4)(x − 7)
c.
3x^2 − 17x − 28
d.
(3x^2 + 4)(x − 7)