Solve the given triangle. round the measures of sides to the nearest tenth and measures of angles to the nearest degree. c = 8, b = 50°, c = 55°
question 15 options:

a. a = 75°, a = 63.6, b = 7.5

b. a = 75°, a = 7.5, b = 9.4

c. a = 75°, a = 9.4, b = 7.5

d. a = 75°, a = 8, b = 7.5

A = , a = 9.4 , and b = 7.5 (which coincides with option C among the listed possible answers)

Step-by-step explanation:

First, we can find the length of side b through the law if sines:

That we can round to 7.5

Now we can find angle A using the property that the addition of all angles in a triangle must equal :

And finally, we can find side "a" by using again the law of sines:

which can be rounded to a = 9.4

isaiah walks 3 miles due north, turns and then 5 miles due east. how far is he from his starting point?

a^2 + b^2 = c^2

let c = distance from starting point.

(3)^2 + (5)^2 = c^2

9 + 25 = c^2

34 = c^2

sqrt{34} = sqrt{c^2}

sqrt{34} = c

answer: can you show the options ?

step-by-step explanation: