Arectangle has a side that is 16 feet and another side there's 1/2 that links a square has a perimeter of 48 feet how much greater is the area of the square in the area of the rectangle

Area of rectangle = 128 square feet

Step-by-step explanation:

Given:- A rectangle with side(a)=16 feet, side (b) = that links to a square.

perimeter (p) = 48 feet.

To find:- area of the square of the rectangle=?

Now,

-------(equation 1)

(8 is half of square of 4=16, )

Now, to find the area of square:-

Area of square (A) = Length breadth

Area of square (A)= side a side b

A= 16 8

A = 128 square feet

Therefore Area of rectangle = 128 square feet

answer: i wpould go with c

step-by-step explanation: