An investor invested a total of $2,300 in two mutual funds. one fund earned a 8% profit while the other earned a 2% profit. if the investors total profit was $82, how much was invested in each mutual fund

the amount invested on the first mutual fund is $600 and the the amount invested on the second mutual fund is $1700

Step-by-step explanation:

Let x represent the amount of money that the investor invested in one mutual fund.

Let y represent the amount of money that the investor invested in the second mutual fund.

An investor invested a total of $2,300 in two mutual funds. This means that

x + y = 2300

Considering the first mutual fund, it earned a 8% profit. This means that amount earned is

8/100 × x = 0.08x

Considering the second mutual fund, it earned a 2% profit. This means that amount earned is

2/100 × y = 0.02y

If the investors total profit was $82, it means that

0.08x + 0.02y = 82 - - - - - - - - 1

Substituting x = 2300 - y into equation 1, it becomes

0.08(2300 - y) + 0.02y = 82

184 - 0.08y + 0.02y = 82

- 0.08y + 0.02y = 82 - 184

- 0.06y = - 102

y = - 102/- 0.06 = 1700

x = 2300 - y = 2300 - 1700

x = 600

i think it's ф or x=6,-6

step-by-step explanation:

-x^2=-36

x^2=-36

ф

or

if you mean by : -(x^2)=-36

it'll be: x^2=36

x=6,x=-6

hope it'll ! have a good day!

you for asking!