Ahelicopter leaves central airport and flies north at 180 mi/hr. twenty minutes later a plane leaves the airport and follows the helicopter at 330mi/hr. how long does it take the plane to overtake the helicopter

Step-by-step explanation:

Let x represent the distance travelled by the helicopter and the plane.

Let t represent the time it takes the the helicopter to travel x miles

Speed of the helicopter is 180 miles per hour.

Distance travelled = speed × time

x = 180t

Twenty minutes later, a plane leaves the airport and follows the helicopter at 330mi/hr. Converting 20 minutes to hours, it becomes 20/60 minutes

Time taken for the plane to travel x miles is t - 20/60

x = 330(t - 20/60)

Before the plane overtakes the helicopter, they would have travelled equal distance. Therefore

330(t - 20/60) = 180t

330t - 110 = 180t

330t - 180t = 110

150t = 110

t = 110/150 = 0.73 hours

i think it's ф or x=6,-6

step-by-step explanation:

-x^2=-36

x^2=-36

ф

or

if you mean by : -(x^2)=-36

it'll be: x^2=36

x=6,x=-6

hope it'll ! have a good day!

you for asking!

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐