If x=3 units, y=11 units, and h=7 what is the area of the trapizoid

area of trapizoid=49 unit^2

Step-by-step explanation:

area of trapizoid=0.5(x+y)h

where, x=parallel side=3units

         y=parallel side =11 units

         h=distance between two parallel sides

area of trapizoid=0.5(x+y)h..............(1)

put x=3 units,y=11 units and h=7 in equ (1)

area of trapizoid=0.5(3+11)7

area of trapizoid=

area of trapizoid=49 unit^2 answer

answer:

c. the third graph

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form